函数f (2x+1)是偶函数,则y=f (x)的对称轴方程为解法一:首先将函数y=f (2x+1)=f [2 (x+0.5)]的图像向右平移0.5个单位,得到函数y=f (2x)的图像,再将图像上各点的横坐标伸长为. 对于@2x的设计来说,1 x 1 pt =2 x 2 px ;对于@3x的设计来说,1 x..
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